Решение cos(2п-2x)+3sin(п-x)=2 cos2x + 3sinx = 2 1 - 2sin²x + 3sinx - 2 = 0 2sin²x - 3sinx + 1 = 0 sinx = t 2t² - 3t + 1 = 0 d = 9 - 4*2*1 = 1 t₁ = (3 - 1)/4 t₁ = 1/2 t₂ = (3 + 1)/4 t₂ = 1 1) sinx = 1/2 x = (-1)^n *arcsin(1/2) + πk, k∈z x₁ = (-1)^n* (π/6) + πk, k∈z 2) sinx = 1 x₂ = π/2 + πn, n∈z
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