Решение 4 tg^2x+tgx-3=0 tgx = t 4t² + t - 3 = 0 d = 1 + 4*4*3 = 49 t₁ = (- 1 - 7)/8 t₁ = - 1 t₂ = (- 1 + 7)/8 t₂ = 3/4 1) tgx = - 1 x₁ = - π/4 + πk, k∈z 2) tgx = 3/4 x₂ = arctg(3/4) + πn, n ∈z ответ: x₁ = - π/4 + πk, k∈z ; x₂ = arctg(3/4) + πn, n ∈z
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