Y=π/4-x tan(x)*tan(π/4-x)=1/6 tan(π/4-x)=(1-tan(x))/(1+tan(x)) tan(x)*(1-tan(x))/(1+tan(x))=1/6 замена: tan(x)=t t≠-1 6*t*(1-t)=1+t 6*t²-5*t+1=0 d=25-24=1 t=(5+-1)/12 t₁=1/3 x=arctan(1/3)+π*n y=π/4-arctan(1/3)-π*n n-целое t₂=1/2 x=arctan(1/2)+π*k y=π/4-arctan(1/2)-π*k k-целое ответ: x=arctan(1/3)+π*n y=π/4-arctan(1/3)-π*n n-целое x=arctan(1/2)+π*k y=π/4-arctan(1/2)-π*k k-целое
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