1) log12 3 + log12 4 2) log7 98 - log7 2 3) log2 5 - log2 35 + log2 56 4) log1/3 5 - log1/3 5 + log1/3 9 как сможете 1) lg4 + lg250 2) log2 6 - log2 6/32 3) (log12 4 + log12 36)^2 4) lg13 - lg130 5) (log2 13 - log2 52)^5 6) (log0,3 9 - 2log0,3 10)^4 решите уравнение 1) log3 x = -1 2) log2 x = -5 3) log3 x = 2 4) log4 x = 3 5) log4 x = -3 6) log7 x = 0 7) log1/7 x = 1 8) log1/2 x = -3 вычислите 1) log2 log2 log3 81 2) log2 log3 log1/3 1/27 3) log√3 log5 125 4) log4 log3 81 как сможете заранее

1) log₁₂3 + log₁₂4 = log₁₂(3*4) = log₁₂12 = 12) log₇98 - log₇2 = log₇(98/2) = log₇49 = 23) log₂5-log₂35 + log₂56 = log₂(5/35) + log₂56 = log₂(log₂8 = 34) log₁/₃5 - log₁/₃5 + log₁/₃ 9 = log₁/₃9 = -21) lg4 + lg250= lg(4*250) = lg1000 = 32) log₂6 - log₂ = log₂( = log₂32 = 53) (log₁₂4 + log₁₂36)² = (log₁₂144)² = 2² = 44) lg13 - lg 130 = lg = lg = -15) (log₂13-log₂52)⁵ = (log₂)⁵ = (log₂)⁵ = (-2)⁵ = -326) (log₀.₃9 - 2log₀.₃10)⁴ = (log₀.₃9 - log₀.₃100)⁴ = (log₀.₃)⁴ = (log₀.₃0.09)⁴ = 2⁴ = 161) log₃x = -1x = 3⁻¹ = 1/32) log₂x = -5x = 2⁻⁵ = 1/323) log₃x = 2x = 3² = 94) log₄x = 3x = 4³ = 645) log₄x = -3x = 4⁻³ = 1/646) log₇x = 0x = 7° = 17) log₁/₇x = 1x = 1/78) log₁/₂x = -3x = (1/2)⁻³ = 81) log₂log₂log₃81 = log₂log₂4 = log₂2 = 12) log₂log₃log₁/₃(1/27) = log₂log₃3 = log₂1 = 03) log₅125 = 3 = 24) log₄log₃81 = log₄4 = 1

х -скорость поезда

60/х-0,2=60/(х+10)

(60(х+10)-0,2х(х+10)-60х)/(х(х+10))=0

х²+10х-3000=0

д=100+12000=12100=110²

х=(-10±110)/2=50; -60

ответ 50 км/ч